MATH SOLVE

4 months ago

Q:
# 2. Consider the quadratic equation 2x2 + 7x – 4 = 0. A. What is the value of the discriminant? Explain. B. How many solutions does the quadratic equation have and are those solutions rational, irrational, or nonreal? Explain. C. If the quadratic equation has real solutions, what are the solutions? Explain. Estimate irrational solutions to the nearest tenth.

Accepted Solution

A:

The value of the discriminant is the value of [tex] b^{2} -4ac[/tex] located inside the square root of the quadratic formula. To find this, we simply look at the quadratic equation in standard form: [tex]a x^{2} +bx+c=0[/tex] and plug in the existing values into the quadratic formula ([tex] \frac{-b+- \sqrt{ b^{2}-4ac } }{2a} [/tex]. Plug in the values of a b and c (2, 7, and -4, respectively) and get [tex] \frac{-7+- \sqrt{49-4(2)(-4)} }{4} [/tex].

Simplifying this, we get

[tex] \frac{-7+- \sqrt{81} }{4} = \frac{-7+-9}{4} = \frac{2}{4} or \frac{-16}{4} [/tex]

which equal 1/2 and -4, respectively.

A )The value of the discriminant is 81 (see work above)

B ) 2 solutions, discriminant is positive, and not equal to zero. They are both rational since sqrt 81 is a rational number

C ) 1/2 and -4 (see work above)

Simplifying this, we get

[tex] \frac{-7+- \sqrt{81} }{4} = \frac{-7+-9}{4} = \frac{2}{4} or \frac{-16}{4} [/tex]

which equal 1/2 and -4, respectively.

A )The value of the discriminant is 81 (see work above)

B ) 2 solutions, discriminant is positive, and not equal to zero. They are both rational since sqrt 81 is a rational number

C ) 1/2 and -4 (see work above)