MATH SOLVE

4 months ago

Q:
# Hooke's law for an elastic spring states that the distance a spring stretches varies directly as the force applied. If a force of 100 newtons stretches a spring 5cm, how much will a force of 360 newtons stretch the same thing?

Accepted Solution

A:

We need to write a proportion

1) Force 1/ length 1 =Force 2/ length 2

100 N/ 5 cm = 360 N/ x cm

x =5*360/100= 18 cm

2) Proportion can be written also as

Length 1/Force 1= Length 2/ Force 2 , and it gives the same result

5 cm/100 N=x cm/360 N

x =5*360/100= 18 cm

1) Force 1/ length 1 =Force 2/ length 2

100 N/ 5 cm = 360 N/ x cm

x =5*360/100= 18 cm

2) Proportion can be written also as

Length 1/Force 1= Length 2/ Force 2 , and it gives the same result

5 cm/100 N=x cm/360 N

x =5*360/100= 18 cm